What is Momentum? Momentum and Its Conservation

Momentum and Its Conservation

How about we guess a speeding truck hits a stationary vehicle because of which the vehicle begins moving. What is really occurring behind the scene? Well here, as the speed of the truck diminishes, the speed of the vehicle increments and consequently the momentum lost by truck is picked up via vehicle. Intriguing? How about we discover progressively about the momentum and its discussion underneath:

What is Momentum?

A vector amount that is the result of the mass and speed of an item or molecule is 'momentum'. Momentum is estimated in the standard unit of kilogram-meter every second (kg • m/s or kg • m • s - 

1 ). The heading of momentum can be communicated in different ways, contingent upon the quantity of measurements included. The heading of momentum is same as the bearing of speed.

Momentum, similar to speed, is relative. Give us a chance to take a 1,000-kg vehicle moving at 20 m/s concerning the outside of a parkway, voyaging northward. On the off chance that the vehicle is driven, the momentum of the vehicle is in respect to the body of the individual driving the vehicle which is zero. And if an individual stands by the side of the street, the momentum of the vehicle in respect to that individual is 20,000 kg • m/s northward.

Direct Momentum

Direct momentum is characterized as a vector amount that is the result of the mass of an item and its speed. Any adjustment in the mass or the speed of the framework causes a change in straight momentum.

Conservation of Momentum

The momentum of a framework is steady if there is no outside power following up on the framework. For a crash happening between two articles in a separated framework, the complete momentum of the two items before the impact is equivalent to the all out momentum of the two articles after the impact.

Induction of Conservation of Momentum

Give us a chance to consider a circumstance wherein: a truck of mass m1, speed u1 and its momentum = m1u1 and a vehicle of mass m2, speed u2 and its momentum m2u2; are moving a similar way yet with various paces. Consequently, all out momentum=m1u1 + m2u2.

Presently assume the vehicle and truck crash for a brief timeframe t, their speeds will change. So now the speed of the truck and vehicle become v1 and v2 individually. Be that as it may, their mass continues as before. Subsequently, presently the all out momentum = m1v1 + m2v2

Increasing speed of vehicle (a) = (v2– u2)/t

Additionally, F = mama

F1 = Force applied by truck on the vehicle

F1 = m2(v2– u2)/t

Increasing speed of truck =(v1– u1)/t

F2 = m1(v1– u1)/t and F1 = – F2

m2(v2– u2)/t = – m1(v1– u1)/t

m2v2– m2u2 = – m1v1+m1u1

or on the other hand m1u1+m2u2 = m2v2+m1v1